| NAME | SYNOPSIS | DESCRIPTION | RETURN VALUE | CONFORMING TO | SEE ALSO | COLOPHON | The Linux Programming Interface |
MEMMOVE(3) Linux Programmer's Manual MEMMOVE(3)
memmove - copy memory area
#include <string.h>
void *memmove(void *dest, const void *src, size_t n);
The memmove() function copies n bytes from memory area src to memory area
dest. The memory areas may overlap: copying takes place as though the bytes
in src are first copied into a temporary array that does not overlap src or
dest, and the bytes are then copied from the temporary array to dest.
The memmove() function returns a pointer to dest.
SVr4, 4.3BSD, C89, C99, POSIX.1-2001.
bcopy(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)
This page is part of release 3.32 of the Linux man-pages project. A
description of the project, and information about reporting bugs, can be found
at http://www.kernel.org/doc/man-pages/.
GNU 1993-04-10 MEMMOVE(3)
HTML rendering created 2010-12-03 by Michael Kerrisk, author of The Linux Programming Interface