From: Paolo Giarrusso Make a UML/i386 instance running on x86_64 pretend to be i386 rather than x86_64. Signed-off-by: Jeff Dike Signed-off-by: Andrew Morton --- arch/um/kernel/user_util.c | 7 ++++++- 1 files changed, 6 insertions(+), 1 deletion(-) diff -puN arch/um/kernel/user_util.c~uml-uml-i386-is-i386-when-running-on-x86_64 arch/um/kernel/user_util.c --- devel/arch/um/kernel/user_util.c~uml-uml-i386-is-i386-when-running-on-x86_64 2005-08-30 00:11:19.000000000 -0700 +++ devel-akpm/arch/um/kernel/user_util.c 2005-08-30 00:11:19.000000000 -0700 @@ -132,7 +132,12 @@ void setup_machinename(char *machine_out struct utsname host; uname(&host); - strcpy(machine_out, host.machine); + /* XXX: crude detection of 32-bit binary. */ + if (sizeof(long) == 4 && !strcmp(host.machine, "x86_64")) { + strcpy(machine_out, "i686"); + } else { + strcpy(machine_out, host.machine); + } } char host_info[(_UTSNAME_LENGTH + 1) * 4 + _UTSNAME_NODENAME_LENGTH + 1]; _